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Here’s an example Python code to print the pattern you described:
# Define a variable to store the number of rows in the pattern
num_rows = 5
# Loop through each row of the pattern
for i in range(1, num_rows+1):
# Print the i-th number i times
for j in range(i):
print(i, end=" ")
# Print a newline character to move to the next row
print()
In this code, we first define a variable num_rows to store the number of rows in the pattern.
We then use a nested loop to print the pattern. The outer loop iterates over each row of the pattern, from 1 to num_rows. The inner loop prints the i-th number (i.e., the value of the outer loop counter) i times, using the end parameter of the print() function to prevent it from adding a newline character after each number. Finally, we use another print() statement without any arguments to add a newline character and move to the next row.
When you run this code, it should output the following pattern:
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Note that you can change the value of num_rows to print the pattern with a different number of rows.
